A Level Chemistry - Chemical Energetics - Hess' Law

By Anonymous (not verified), 22 April, 2026

Energy cyclesConsider the reaction: A + B → C + D Here we are only observing one possible reaction route from the reactants A and B to the products C and D. In fact there may be more than one possible route for this reaction to take. Example: According to the German scientist Hess, the total enthalpy change for a chemical reaction is independent of the route by which the reaction takes place. If we take the example above then the enthalpy change of route 1 would equal the total of the enthalpy changes for route 2:Δ H1 = Δ H2 + Δ H3 + Δ H4Application of Hess' lawThe best way to calculate this is to use different routes as shown. Where we cannot measure enthalpy changes directly Hess' law is of great use. Consider the following example for the formation of methane from carbon and hydrogen: We are unable to perform this reaction in the laboratory but we can use the values for the enthalpy of combustion for the elements and compound. (Note: O2(g) is included on both sides of the equation in order to balance the equations. Its presence does not affect the enthalpy change.) Δ H2 = Δ Hc o Carbon (Graphite) = -393.5 kJmol-1Δ H3 = Δ Hc o Hydrogen = -285.8 kJmol-1Δ H4 = Δ Hc o Methane = -890.3 kJmol-1We can also use Hess's law to help calculate the average bond energy for C-H in methane: Δ H2 = -74.8 kJ mol1Δ H3 = +715 kJ mol-1Δ H4 = +218 kJ mol-1 Δ H1 = Δ H3 + 4Δ H4 - Δ H2Δ H1 = +715 + 4(218) - (-74.8) = + 1661.8 kJ mol-14 C-H bonds in methane therefore:1 C-H bond = 1661.8/4 = +415.3 kJ mol-1